dtthanhb1ts419 dtthanhb1ts419
  • 02-08-2021
  • Mathematics
contestada

solve the equation[tex]x^3+\left(y^'\right)^3-3xy^'\:=0[/tex]

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SabinaIbragimova361
SabinaIbragimova361 SabinaIbragimova361
  • 02-08-2021

Answer:0

Step-by-step explanation:

3x=3xy

x=0

y=0

3 times 0 = 0

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8 + |x -2| = 8|x + 1| +5 = 24|x - 3|= -163|x +10| = 0
factored form 20x^3+33x^2+7x