Verify the identity.

cot^2x/ cscx-1 = 1+sinx/sinx

Question

02-10-2016
Mathematics

contestada

Verify the identity.

cot^2x/ cscx-1 = 1+sinx/sinx

Respuesta :

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Maria81 Maria81 · Answer 1 · 2016-10-02T01:54:08+02:00

cot²x /(cscx + 1) = (1 - sinx) /sinx

let's apply the identity cot²x = csc²x - 1:

(csc²x - 1) /(cscx + 1) = (1 - sinx) /sinx

(factoring csc²x - 1 as a difference of squares and then simplifying)

[(cscx + 1)(cscx - 1)] /(cscx + 1) = (1 - sinx) /sinx

cscx - 1 = (1 - sinx) /sinx

let's recall that cscx = 1 /sinx:

(1 /sinx) - 1 = (1 - sinx) /sinx

ending with:

(1 - sinx) /sinx = (1 - sinx) /sinx (verified)

I hope it helps

Verify the identity. cot^2x/ cscx-1 = 1+sinx/sinx

Respuesta :

Otras preguntas

Verify the identity.

cot^2x/ cscx-1 = 1+sinx/sinx