kapin644 kapin644

02-05-2020
Mathematics

contestada

write an equation for a circle with a radius of 3 and a center located at point (2,-1)

Respuesta :

mysticchacha mysticchacha

02-05-2020

Answer:

(x - 2)^2 + (y + 1)^2 = 9

Step-by-step explanation:

recall the equation for a circle:

(x - h)^2 + (y - k)^2 = r^2

here (h, k) = (2, -1)

and r = 3

so

(x - 2)^2 + (y -(-1))^2 = 3^2

(x - 2)^2 + (y + 1)^2 = 3^2

(x - 2)^2 + (y + 1)^2 = 9

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